Equations for Uniform Acceleration

Here, we shall learn a few equations that will be useful for calculations involving uniform acceleration.

Lets start with the one we already know:

1. Acceleration = (final velocity - initial velocity) / time taken:

a = (v - u)/t

The first new equation we shall derive is:

2. Displacement = average velocity x time

s = (u + v)/2 x t

This is obtained using the property that the area under a velocity-time graph is the displacement. Suppose that a body with a velocity u is accelerated uniformly to velocity v over a time t. The velocity-time graph is a straight line, and the area under it is a trapezium.

The area = 1/2 x sum of parallel sides x distance between them = 1/2 x (u + v) x t. This is just the equation above.

The next equation is

3. Displacement = initial velocity x time + half acceleration x time squared

s = ut + at2/2

This is obtained by combining the above equations 1 and 2. First, rearrange eq. 1 to give

v = u + at.

Next, substitute into eq. 2 like this:

s = (u + u + at)/2 x t
Simplifying:
s = (2u + at)/2 x t = (u + at/2) x t = ut + at2/2
we get eq. 3.

The last equation is

4. Final velocity squared = Initial velocity squared + twice acceleration x displacement

v2 = u2 + 2as.

This is again obtained from eqs. 1 and 2, by combining them in a different way. This time, we multiply them directly:

as = (v - u)/t x (u + v)/2 x t.
Simplifying, expanding
as = (v - u) x (u + v)/2 = (v2 - u2)/2
and rearranging:
2as = v2 - u2
gives eq. 3
u2 + 2as = v2.

The four equations are summarised here:
1.

a = (v - u)/t, or v = u + at
2.
s = (u + v)/2 x t
3.
s = ut + at2/2
4.
v2 = u2 + 2as.



Copyright 2010 by Kai Hock. All rights reserved.
Last updated: 28 November 2010.